嘗試更改動態生成的列在行中的位置
需要將洗掉按鈕的位置更改到末尾。
在左端洗掉的作業腳本
<HTML>
<HEAD>
<SCRIPT>
function addRow(tableID) {
var table = document.getElementById(tableID);
var rowCount = table.rows.length;
var row = table.insertRow(rowCount);
//Column 1
var cell1 = row.insertCell(0);
var element1 = document.createElement("input");
element1.type = "button";
var btnName = "button" (rowCount 1);
element1.name = btnName;
element1.setAttribute('value', 'Delete'); // or element1.value = "button";
element1.onclick = function () { removeRow(btnName); } ;
cell1.appendChild(element1);
//Column 2
var cell2 = row.insertCell(1);
cell2.innerHTML = rowCount 1;
//Column 3
var cell3 = row.insertCell(2);
var element3 = document.createElement("input");
element3.type = "text";
cell3.appendChild(element3);
}
function removeRow(btnName) {
try {
var table = document.getElementById('dataTable');
var rowCount = table.rows.length;
for (var i = 0; i < rowCount; i ) {
var row = table.rows[i];
var rowObj = row.cells[0].childNodes[0];
if (rowObj.name === btnName) {
table.deleteRow(i);
rowCount--;
}
}
}
catch (e) {
alert(e);
}
}
</SCRIPT>
</head>
<body>
<INPUT type="button" value="Add Row" onclick="addRow('dataTable')" />
<TABLE id="dataTable" width="350px" border="1">
<TR>
<TD><input type="button" name="button1" value="Delete" onclick="removeRow('button1')"></TD>
<TD>1</TD>
<TD><input type="text" value="" name="nameTxt"></TD>
</TR>
</TABLE>
</BODY>
</HTML>
修改版
<HTML>
<HEAD>
<SCRIPT>
function addRow(tableID) {
var table = document.getElementById(tableID);
var rowCount = table.rows.length;
var row = table.insertRow(rowCount);
//Column 2
var cell1 = row.insertCell(0);
cell1.innerHTML = rowCount 1;
//Column 3
var cell2 = row.insertCell(1);
var element2 = document.createElement("input");
element2.type = "text";
cell2.appendChild(element2);
//Column 1
var cell3 = row.insertCell(2);
var element3 = document.createElement("input");
element3.type = "button";
var btnName = "button" (rowCount 1);
element3.name = btnName;
element3.setAttribute('value', 'Delete'); // or element1.value = "button";
element3.onclick = function () { removeRow(btnName); } ;
cell3.appendChild(element3);
alert(btnName);
}
function removeRow(btnName) {
try {
var table = document.getElementById('dataTable');
var rowCount = table.rows.length;
for (var i = 0; i < rowCount; i ) {
var row = table.rows[i];
var rowObj = row.cells[2].childNodes[2];
if (rowObj.name === btnName) {
table.deleteRow(i);
rowCount--;
}
}
}
catch (e) {
alert(e);
}
alert(btnName);
}
</SCRIPT>
</HEAD>
<BODY>
<form action="AddnewcustProgram.jsp">
<TABLE id="dataTable">
<TR>
<TD>1</TD>
<TD><input type="text" value="" name="nameTxt"></TD>
<TD><input type="button" name="button1" value="Delete" onclick="removeRow('button1')"></TD>
</TR> </TABLE>
<table>
<tr>
<td>
<INPUT type="button" value="Add Row" onclick="addRow('dataTable')" /></td>
<td>
<input type="submit" value="Execute" >
</td>
</tr>
</table>
</form>
</BODY>
</HTML>
嘗試像上面那樣修改腳本。但是單擊它時洗掉不起作用。如果需要任何進一步的細節，請告訴我。非常感謝您的支持。
uj5u.com熱心網友回復：
改變這個
var rowObj = row.cells[2].childNodes[2];
對此
var rowObj = row.cells[2].childNodes[0];
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