我需要為每個鍵的串列中的每個值創建一個新的字典
dict = {'app_clicks': [56, 65, 41, 40, 64],
'billed_charge_local_micro': [219941307,
247274715,
181271175,
164359644,
223745830],
'billed_engagements': [85831, 89976, 60566, 55304, 88839],
'card_engagements': None,
'carousel_swipes': None,
'clicks': [322, 351, 225, 197, 337],
'engagements': [363, 397, 258, 233, 383],
'follows': None,
'impressions': [86236, 90763, 60596, 55689, 88916],
'likes': [4, 2, 3, 1, 8],
'media_engagements': [41, 45, 33, 36, 46],
'media_views': [33533, 35665, 23611, 21957, 35792],
'poll_card_vote': None,
'qualified_impressions': None,
'replies': [0, 1, 0, 0, 0],
'retweets': None,
'tweets_send': None,
'unfollows': None,
'url_clicks': [56, 65, 41, 40, 64],
'video_15s_views': [27859, 29801, 19852, 18974, 30373],
'video_3s100pct_views': [16441, 17699, 11112, 10337, 16993],
'video_6s_views': [17332, 18785, 12126, 11517, 18663],
'video_content_starts': [81824, 85312, 58449, 53392, 84893],
'video_cta_clicks': None,
'video_total_views': [33533, 35665, 23611, 21957, 35792],
'video_views_100': [27861, 29774, 19840, 18982, 30386],
'video_views_25': [72137, 75452, 51049, 46138, 74744],
'video_views_50': [48377, 50961, 34242, 31603, 51323],
'video_views_75': [35233, 37444, 24959, 23430, 38004]}
基本上我需要為串列中的每個值創建一個包含字典的新串列。
所以它會是這樣的
new_list_with_dicts = [
{ "billed_charge_local_micro" : 219941307,
"clicks": 322,
"impressions" : 86236,
},
{ "billed_charge_local_micro" : 247274715,
"clicks": 351,
"impressions" : 90763,
},
{ "billed_charge_local_micro" : 181271175,
"clicks": 225,
"impressions" : 60596,
},
]
這是我嘗試過的方法之一:
i = 0
list_data = []
dict = {}
for key,value in report.items():
if isinstance(value, list):
while i < len(value):
dict[key] = value[i]
pprint.pprint(dict)
i = i 1
i = 0
但它正在創建具有重復值的字典,顯然是針對每個陣列的最后一項
我希望我能解釋清楚
我被困在這所以任何幫助將不勝感激。
提前致謝
uj5u.com熱心網友回復:
我相信這可以解決問題,看起來你幾乎就在那里,但弄亂了一些語法
list_data = [{} for i in range(len(list(report.values())[0]))]
for key,value in report.items():
if isinstance(value, list):
for i in range(len(value)):
list_data[i][key] = value[i]
print(list_data)
假設您的字典存盤在報告中,這應該回傳所需的輸出
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