我被困在這個問題上，我希望有人可以幫助我。我有一個要按特定鍵分組的陣列。唯一的問題是，每當回圈期間鍵的值發生變化時，我都想擁有一個新陣列。這是陣列的一個示例。
Array
(
[0] => Array
(
[id] => 972
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
[1] => Array
(
[id] => 644
[user_id] => 2
[user_field_48] => 4
[project] => 123 — QHV
[duration] => 15:00
[grouped_by] => 4
)
[2] => Array
(
[id] => 631
[user_id] => 2
[user_field_48] => 4
[project] =>
[duration] => -5:00
[grouped_by] => 4
)
[3] => Array
(
[id] => 630
[user_id] => 2
[user_field_48] => 1
[project] =>
[duration] => 22:00
[grouped_by] => 1
)
[4] => Array
(
[id] => 971
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
[5] => Array
(
[id] => 973
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
[6] => Array
(
[id] => 974
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
)
我做了
foreach($report_items as $item)
{
$groupedItems[$item['grouped_by']][] = $item;
}
我得到了
Array
(
[1] => Array
(
[0] => Array
(
[id] => 972
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
[1] => Array
(
[id] => 630
[user_id] => 2
[user_field_48] => 1
[project] =>
[duration] => 22:00
[grouped_by] => 1
)
[2] => Array
(
[id] => 971
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
[3] => Array
(
[id] => 973
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
[4] => Array
(
[id] => 974
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
)
[4] => Array
(
[0] => Array
(
[id] => 644
[user_id] => 2
[user_field_48] => 4
[project] => 123 — QHV
[duration] => 15:00
[grouped_by] => 4
)
[1] => Array
(
[id] => 631
[user_id] => 2
[user_field_48] => 4
[project] =>
[duration] => -5:00
[grouped_by] => 4
)
)
)
我實際上正在尋找的是這樣的東西，其中陣列在回圈期間是分開的，并且每當值更改時都會將后綴添加到鍵中。
Array
(
[1.1] => Array
(
[0] => Array
(
[id] => 972
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
)
[4.1] => Array
(
[0] => Array
(
[id] => 644
[user_id] => 2
[user_field_48] => 4
[project] => 123 — QHV
[duration] => 15:00
[grouped_by] => 4
)
[1] => Array
(
[id] => 631
[user_id] => 2
[user_field_48] => 4
[project] =>
[duration] => -5:00
[grouped_by] => 4
)
)
[1.2] => Array
(
[0] => Array
(
[id] => 630
[user_id] => 2
[user_field_48] => 1
[project] =>
[duration] => 22:00
[grouped_by] => 1
)
[1] => Array
(
[id] => 971
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
[2] => Array
(
[id] => 973
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
[3] => Array
(
[id] => 974
[user_id] => 2
[user_field_48] => 1
[project] => 100 — NLO
[duration] => 1:00
[grouped_by] => 1
)
)
)
我真的不知道解決此問題的簡單方法，因此我將不勝感激。謝謝！
uj5u.com熱心網友回復：
不必費心在這里重新創建您的完整陣列，我使用的是只有 id 和 grouped_by 值的簡化版本，但是如果您使用“完整”陣列進行操作，原理當然是完全相同的。
我正在使用一個計數器陣列來跟蹤我們當前正在處理的特定組的哪個“迭代”。在經典的控制中斷實作邏輯中，我將當前記錄的 grouped_by 與前一個記錄進行比較 - 如果它們不同，則該 grouped_by 值的計數器必須增加 1。然后，我只是創建要使用的陣列鍵，通過組合 grouped_by 值和它的當前計數。
$data = [['id' => 972, 'grouped_by' => 1], ['id' => 664, 'grouped_by' => 4], ['id' => 631, 'grouped_by' => 4], ['id' => 630, 'grouped_by' => 1], ['id' => 971, 'grouped_by' => 1], ['id' => 973, 'grouped_by' => 1], ['id' => 974, 'grouped_by' => 1]];
$grouped_result = $grouped_by_counts = [];
$previous_grouped_by = null; // a value that will never occur in the data
foreach($data as $datum) {
if($datum['grouped_by'] !== $previous_grouped_by) {
$grouped_by_counts[$datum['grouped_by']] =
isset($grouped_by_counts[$datum['grouped_by']]) ?
$grouped_by_counts[$datum['grouped_by']] 1 : 1;
}
$grouped_result[
$datum['grouped_by'].'.'.$grouped_by_counts[$datum['grouped_by']]
][] = $datum;
$previous_grouped_by = $datum['grouped_by'];
}
print_r($grouped_result);
現場示例：https ://3v4l.org/odtie
轉載請註明出處，本文鏈接：https://www.uj5u.com/ruanti/438474.html