我正在嘗試遍歷存盤為“Person”物件的“_skills”屬性的哈希陣列,但遇到了麻煩。
測驗1.pl
my $person = new Person( "Hubert", "Blu",
[
{"name" => "Python", "Weight" => 80, "group","IT SKILLS", "id"=>0002},
{"name" => "Magic", "Weight" => 100, "group", "MISC SKILLS", "id"=>0001},
{"name" => "JavaScript","Weight" => 70, "group"=> "IT SKILLS", "id"=>0004},
{"name" => "Mage","Weight" => 100, "group"=>"JOB TITLE", "id" =>0003},
{"name" => "Assassin", "Weight" => 85, "group"=>"JOB TITLE"}
]
);
和 Person.pl
sub new {
my ($class,$first_name,$last_name,@skills) = @_ ;
my $self = {};
$self->{"_first_name"} = $first_name;
$self->{"_last_name"} = $last_name;
@{$self->{"_skills"}} = @skills;
# Print all the values just for clarification.
print "First Name is $self->{_first_name}\n";
print "Last Name is $self->{_last_name}\n";
print "Skills : " . Data::Dumper::Dumper($self->{_skills}) . "\n";
print"---SKILLS---\n";
my $i = 1;
foreach my $skill_set (@{$self->{_skills}}) {
print "skill ".$i .": \n";
$i ;
#print Data::Dumper::Dumper($skill_set) . "\n";
print "$skill_set->{'_first_name'}";
};
bless $self, $class;
return $self;
}
第一個轉儲顯示了陣列,它看起來很好。回圈內的第二個轉儲再次顯示整個陣列,它只回圈一次,然后完成以下錯誤
Not a HASH reference at /home/izoom/PerlTrainingGround/LeeR/lib/Person/Person.pm line 26.
被困了幾個小時,任何幫助一如既往地受到贊賞!
uj5u.com熱心網友回復:
您將三個引數傳遞給newplus 呼叫者。最后一個是對陣列的參考。這意味著@skills最終會得到一個元素,其值為該參考。
my $person = new Person( "Hubert", "Blu",
[
{"name" => "Python", "Weight" => 80, "group","IT SKILLS", "id"=>0002},
{"name" => "Magic", "Weight" => 100, "group", "MISC SKILLS", "id"=>0001},
{"name" => "JavaScript","Weight" => 70, "group"=> "IT SKILLS", "id"=>0004},
{"name" => "Mage","Weight" => 100, "group"=>"JOB TITLE", "id" =>0003},
{"name" => "Assassin", "Weight" => 85, "group"=>"JOB TITLE"}
]
);
應該
my $person = new Person( "Hubert", "Blu",
{"name" => "Python", "Weight" => 80, "group","IT SKILLS", "id"=>0002},
{"name" => "Magic", "Weight" => 100, "group", "MISC SKILLS", "id"=>0001},
{"name" => "JavaScript","Weight" => 70, "group"=> "IT SKILLS", "id"=>0004},
{"name" => "Mage","Weight" => 100, "group"=>"JOB TITLE", "id" =>0003},
{"name" => "Assassin", "Weight" => 85, "group"=>"JOB TITLE"}
);
要么
my ($class,$first_name,$last_name,@skills) = @_ ;
@{$self->{"_skills"}} = @skills; # Useless shallow array copy
# -or-
$self->{"_skills"} = [ @skills ]; # Same[1] but clearer
# -or-
$self->{"_skills"} = \@skills; # No copy of elements
應該
my ($class,$first_name,$last_name,$skills) = @_ ;
@{$self->{"_skills"}} = @$skills; # Shallow array copy
# -or-
$self->{"_skills"} = [ @$skills ]; # Same[1] but clearer
# -or-
$self->{"_skills"} = $skills; # No copy of elements
- 既然
$self->{"_skills"}是undef在這一點上。
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標籤:perl
