我想將Ay 軸上的矩陣值繪制為 x 軸上節點數的函式。但是，由于我有一個 5x5 矩陣，我不希望手動定義節點號。例如，節點 1 對應 2.53734572e-01，節點 2 對應 -1.08940733e-01，...，節點 6 對應 -5.02000098e-01 等等。
import numpy as np
import matplotlib.pyplot as plt
Node=np.array([[1,2,3,4,5],[6,7,8,9,10]])
A=np.array([[ 2.53734572e-01, -1.08940733e-01, 3.26138649e-03,
-6.10246692e-03, -2.59115145e-02],
[-5.02000098e-01, 1.08933714e-01, -3.65540228e-02,
5.93536044e-03, 3.88767438e-02],
[-1.42775456e 00, 4.52103243e-01, -2.33067190e-02,
7.27554880e-03, 1.15638039e-01],
[ 4.81030592e-01, -8.91302226e-02, 1.40486724e-03,
2.28801066e-02, -3.83389182e-02],
[ 8.39965176e-01, -2.81589587e-01, 2.24843962e-01,
-8.47758268e-03, -6.84721033e-02]])
plt.scatter(Node, A)
plt.xlabel('Node')
plt.ylabel('Velocity')
uj5u.com熱心網友回復：
我們可以將矩陣縮減為一維，并在矩陣的長度上使用numpy.arange：
import numpy as np
import matplotlib.pyplot as plt
ys=np.array([[ 2.53734572e-01, -1.08940733e-01, 3.26138649e-03,
-6.10246692e-03, -2.59115145e-02],
[-5.02000098e-01, 1.08933714e-01, -3.65540228e-02,
5.93536044e-03, 3.88767438e-02],
[-1.42775456e 00, 4.52103243e-01, -2.33067190e-02,
7.27554880e-03, 1.15638039e-01],
[ 4.81030592e-01, -8.91302226e-02, 1.40486724e-03,
2.28801066e-02, -3.83389182e-02],
[ 8.39965176e-01, -2.81589587e-01, 2.24843962e-01,
-8.47758268e-03, -6.84721033e-02]]).flatten()
nodes=np.arange(len(y))
plt.scatter(nodes, ys)
plt.xlabel('Node')
plt.ylabel('Velocity')
plt.show()
輸出
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標籤：Python 麻木的 matplotlib