在mathplotlib中將x標題從秒轉換為分鐘

如何將 x 軸的標題從秒轉換為分鐘？

有了這些資料，我在幾秒鐘內生成了 10xx、20xx、30xx 和 40xx 的標簽，因為資料在幾秒鐘內還有一個 x 標簽。

不幸的是，為了能夠輕松地對值進行分類，它應該是幾分鐘，最好是在偶數時間，例如每 30 或 60 分鐘，具體取決于資料量。

x 軸的標簽應該是這樣的： [60,120,180, 240,...]

df = pd.DataFrame(data)
df = df[['seconds', 'marker', 'data1', 'data2', 'data3']]
ax = df.set_index('seconds').plot(kind='bar', stacked=True, alpha=set_alpha)
ax.xaxis.set_major_locator(plt.MaxNLocator(5))
plt.plot(df.index, df['data1'], linestyle='solid', color='blue', alpha=0.4, label='data1')
plt.show()

資料示例：

seconds,marker,data1,data2,data3,data4
0,B,0,0,0,0
59,C,42,8,369000,0
74,B,42,8,369000,283041
121,B,42,8,369000,283041
179,B,42,8,369000,283041
239,B,42,8,369000,283041
304,B,42,8,369000,283041
360,B,42,8,369000,283041
377,A,42,8,369000,283041
420,B,42,8,369000,283041
493,B,42,8,369000,283041
540,B,42,8,369000,283041
600,B,42,8,369000,283041
659,B,42,8,369000,283041
719,B,64,8,412000,283041
780,B,64,8,412000,283041
840,B,64,8,412000,283041
880,A,64,8,412000,283041
900,B,64,8,412000,283041
961,B,64,8,412000,283041
1020,B,64,8,412000,283041
1079,B,64,8,412000,283041
1141,B,64,8,412000,283041
1200,B,64,8,412000,283041
1260,B,64,8,412000,283041
1320,B,64,8,412000,283041
1365,A,64,8,412000,283041
1382,B,64,8,412000,283041
1440,B,64,8,412000,283041
1498,B,64,8,412000,283041
1559,B,64,8,412000,283041
1621,B,64,8,412000,283041
1679,B,64,8,412000,283041
1740,B,64,8,412000,283041
1800,B,42,8,369000,283041
1830,A,42,8,369000,283041
1867,B,42,8,369000,283041
1921,B,42,8,369000,283041
1979,B,42,8,369000,283041
2040,B,42,8,369000,283041
2099,B,42,8,369000,283041
2159,B,42,8,369000,283041
2220,B,42,8,369000,283041
2272,A,42,8,369000,283041
2288,B,42,8,369000,283041
2341,B,42,8,369000,283041
2400,B,42,8,369000,283041
2460,B,42,8,369000,283041
2520,B,42,8,369000,283041
2579,B,42,8,369000,283041
2640,B,42,8,369000,283041
2700,B,42,8,369000,283041
2720,A,42,8,369000,283041
2759,B,42,8,369000,283041
2833,B,28,14,248000,260096
2880,B,28,14,248000,247808
2940,B,14,28,124000,123904
3000,B,0,42,0,0
3060,B,0,42,0,0
3120,B,0,42,0,0
3136,A,0,42,0,0
3180,B,0,42,0,0
3251,B,0,42,0,0
3267,D,0,42,0,0
3300,B,0,42,0,0
3359,B,0,42,0,0
3419,B,0,42,0,0
3538,B,0,0,0,0
3599,B,0,0,0,0
3643,C,140,4,1260000,0

uj5u.com熱心網友回復：

我認為您可以使用 .set_xticks(ticks, labels=labels)。這是一個例子：

import pandas as pd
import numpy as np

data = pd.read_csv(r"your_data_in_a_txt_file.txt")

t = data.seconds

max_t = np.max(t) # seconds
max_t = max_t/60 # minutes
max_t = max_t/30 # half hours
max_t = np.floor(max_t) # round downwards

ticks = np.arange(0,max_t 1) # Now we know have many ticks you need
labels = ["%.1f h" % (x/2) for x in ticks] # Generate tick labels
xticks = ticks*30*60 # and the actual positions of the ticks

fig, ax = plt.subplots()
for col in ["data1","data2","data3","data4"]:
    ax.plot(t, data[col], label=col)
ax.set_xticks(xticks, labels=labels)
plt.legend()
plt.show()

標籤：熊猫 数据框 matplotlib 阴谋

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