檢查是否釋放了多個按鈕androidstudio/java

我希望我的程式只有在所有按鈕都被釋放時才發送 0。當我釋放按鈕時，代碼現在發送 0，但如果我按住按鈕并釋放其中一個，它將發送 0，但我不希望它這樣做，我只希望在所有按鈕都被釋放時。謝謝。

@Override
    public boolean onTouch(View view, MotionEvent motionEvent) {
        switch (view.getId()){
            case R.id.commend1B:
                if (motionEvent.getAction() == ACTION_DOWN) {
                    commend1BHold = true;
                    Log.i("sending", "sending 1");
                    bluetooth.write("1#");
                } else if (motionEvent.getAction() == ACTION_UP){
                    Log.i("sending", "sending 0");
                    bluetooth.write("0#");
                }
                break;
            case R.id.commend2B:
                if (motionEvent.getAction() == ACTION_DOWN) {
                    Log.i("sending", "sending 2");
                    bluetooth.write("2#");

                } else if (motionEvent.getAction() == ACTION_UP){
                    Log.i("sending", "sending 0");
                    bluetooth.write("0#");
                }
                break;
            case R.id.commend3B:
                if (motionEvent.getAction() == ACTION_DOWN) {
                    Log.i("sending", "sending 3");
                    bluetooth.write("3#");
                } else if (motionEvent.getAction() == ACTION_UP){
                    Log.i("sending", "sending 0");
                    bluetooth.write("0#");
                }
                break;
            case R.id.commend4B:
                if (motionEvent.getAction() == ACTION_DOWN) {
                    Log.i("sending", "sending 4");
                    bluetooth.write("4#");
                } else if (motionEvent.getAction() == ACTION_UP){
                    Log.i("sending", "sending 0");
                    bluetooth.write("0#");
                }
                break;


            default:
                throw new IllegalStateException("Unexpected value: "   view.getId());
        }

        return false;
    }

uj5u.com熱心網友回復：

每次釋放按鈕（任何按鈕）時，呼叫一個方法來檢查是否釋放了所有按鈕。如果是，請發送0.

還可以對按下的按鈕進行計數：每次按下按鈕時，計數器都會增加，反之亦然。如果計數器為零，則發送0.

uj5u.com熱心網友回復：

做了這樣的事情：

@Override
    public boolean onTouch(View view, MotionEvent motionEvent) {
        switch (view.getId()){
            case R.id.commend1B:
                if (motionEvent.getAction() == ACTION_DOWN) {
                    commend1BHold = true;
                    Log.i("sending", "sending 1");
                    bluetooth.write("1#");
                } else if (motionEvent.getAction() == ACTION_UP){
                    commend1BHold = false;
                    send0();

                }
                break;
            case R.id.commend2B:
                if (motionEvent.getAction() == ACTION_DOWN) {
                    commend2BHold = true;
                    Log.i("sending", "sending 2");
                    bluetooth.write("2#");

                } else if (motionEvent.getAction() == ACTION_UP){
                    commend2BHold = false;
                    send0();
                }
                break;
            case R.id.commend3B:
                if (motionEvent.getAction() == ACTION_DOWN) {
                    commend3BHold = true;
                    Log.i("sending", "sending 3");
                    bluetooth.write("3#");
                } else if (motionEvent.getAction() == ACTION_UP){
                    commend3BHold = false;
                    send0();
                }
                break;
            case R.id.commend4B:
                if (motionEvent.getAction() == ACTION_DOWN) {
                    commend4BHold = true;
                    Log.i("sending", "sending 4");
                    bluetooth.write("4#");
                } else if (motionEvent.getAction() == ACTION_UP){
                    commend4BHold = false;
                    send0();
                }
                break;


            default:
                throw new IllegalStateException("Unexpected value: "   view.getId());
        }

        return false;
    }
    public void send0(){
        if(!commend1BHold &&!commend2BHold && !commend3BHold && !commend4BHold){
            Log.i("sending", "sending 0");
            bluetooth.write("0#");
        }
    }

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