假設我嵌套了下面的 ruby?? 哈希
hash_or_array = [{
"book1" => "buyer1",
"book2" => {
"book21" => "buyer21", "book22" => ["buyer23", "buyer24", true]
},
"book3" => {
"0" => "buyer31", "1" => "buyer32", "2" => "buyer33",
"3" => [{
"4" => "buyer34",
"5" => [10, 11],
"6" => [{
"7" => "buyer35"
}]
}]
},
"book4" => ["buyer41", "buyer42", "buyer43", "buyer35"],
"book5" => {
"book5,1" => "buyer5"
}
}]
我想尋找字串buyer35。匹配后，它應該回傳以下內容
[
{
"book3" => {
"0" => "buyer31", "1" => "buyer32", "2" => "buyer33",
"3" => [{
"4" => "buyer34",
"5" => [10, 11],
"6" => [{
"7" => "buyer35"
}]
}]
}
},
{
"book4" => ["buyer41", "buyer42", "buyer43", "buyer35"]
}
]
下面的解決方案（來自另一個 SO 問題，下面的鏈接）回傳第一個匹配項，但我試圖弄清楚如何回傳多個匹配項
def recurse(obj, target)
case obj
when Array
obj.each do |e|
case e
when Array, Hash
rv = recurse(e, target)
return [rv] unless rv.nil?
when target
return e
end
end
when Hash
obj.each do |k,v|
case v
when Array, Hash
rv = recurse(v, target)
return {k=>rv} unless rv.nil?
when target
return {k=>v}
end
end
end
nil
end
這是原始的問題和答案：如何搜索嵌套的哈希陣列和哈希陣列并且只從父節點回傳匹配的物件？
更新：正確的回傳格式應該是
[
{
"book3" => {
"3" => [{
"6" => [{
"7" => "buyer35"
}]
}]
}
},
{
"book4" => ["buyer41", "buyer42", "buyer43", "buyer35"]
}
]
uj5u.com熱心網友回復：
這是一個在任何嵌套陣列或散列中遞回搜索目標值的函式。然后使用該函式在頂級 hash_or_array 中選擇包含目標的條目并將它們添加到陣列中。
require 'pp'
def find_value(obj, target, found = false)
found = true if obj == target
return found unless obj.is_a?(Array) || obj.is_a?(Hash)
case obj
when Hash
obj.each { |k, v| found = find_value(v, target, found) }
when Array
obj.each { |v| found = find_value(v, target, found) }
end
found
end
found_entries = hash_or_array.inject([]) {|entries, obj| entries << obj.select { |k, v| find_value({ k => v }, "buyer35") }}
pp found_entries
=>
[{"book3"=>
{"0"=>"buyer31",
"1"=>"buyer32",
"2"=>"buyer33",
"3"=>[{"4"=>"buyer34", "5"=>[10, 11], "6"=>[{"7"=>"buyer35"}]}]},
"book4"=>["buyer41", "buyer42", "buyer43", "buyer35"]}]
uj5u.com熱心網友回復：
下面的代碼似乎為這種特定情況生成了所需的輸出：
hash_or_array.inject([]) do |result, x|
x.keep_if { |k, v| v.to_s =~ /buyer35/ }
result << x
end
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