XSL從父元素中選擇值，如果兩個子元素具有特定值

我有以下 XML。如果address component存在一個元素，該元素同時type具有值??為“sublocality”的type元素和值為“sublocality_level_1”的元素，那么我想address component為long_name.

在下面的示例 XML 中，這將是“Vleuten-De Meern”

我試過的：

    Dim myXML As New XmlDocument
    Dim responseString As String = "<GeocodeResponse><status>OK</status><result><type>political</type><type>sublocality</type><type>sublocality_level_2</type><formatted_address>De Meern, Utrecht, Netherlands</formatted_address><address_component><long_name>De Meern</long_name><short_name>De Meern</short_name><type>political</type><type>sublocality</type><type>sublocality_level_2</type></address_component><address_component><long_name>Vleuten-De Meern</long_name><short_name>Vleuten-De Meern</short_name><type>political</type><type>sublocality</type><type>sublocality_level_1</type></address_component><address_component><long_name>Utrecht</long_name><short_name>Utrecht</short_name><type>locality</type><type>political</type></address_component><address_component><long_name>Utrecht</long_name><short_name>Utrecht</short_name><type>administrative_area_level_2</type><type>political</type></address_component><address_component><long_name>Utrecht</long_name><short_name>UT</short_name><type>administrative_area_level_1</type><type>political</type></address_component><address_component><long_name>Netherlands</long_name><short_name>NL</short_name><type>country</type><type>political</type></address_component><geometry><location><lat>52.0757940</lat><lng>5.0319779</lng></location><location_type>APPROXIMATE</location_type><viewport><southwest><lat>52.0714898</lat><lng>5.0196140</lng></southwest><northeast><lat>52.0904459</lat><lng>5.0484669</lng></northeast></viewport><bounds><southwest><lat>52.0714898</lat><lng>5.0196140</lng></southwest><northeast><lat>52.0904459</lat><lng>5.0484669</lng></northeast></bounds></geometry><place_id>ChIJx5fkM1RlxkcR_pIQJLtl5Ro</place_id></result></GeocodeResponse>"
    myXML.LoadXml(responseString)

    If myXML.SelectSingleNode("GeocodeResponse/result[address_component[type[. = 'sublocality']] and address_component[type[. = 'sublocality_level_1']]]") IsNot Nothing Then
        Log("found")
        neighborhood = myXML.SelectSingleNode("GeocodeResponse/result[address_component[type[. = 'sublocality']] and address_component[type[. = 'sublocality_level_1']]]/long_name").InnerText            
    Else
        Log("NOT found")
    End If

找到該元素，記錄一個值“找到”，但是當我想檢索我得到的值時：

“你呼叫的物件是空的。”

<GeocodeResponse>
    <status>OK</status>
    <result>
        <type>political</type>
        <type>sublocality</type>
        <type>sublocality_level_2</type>
        <formatted_address>De Meern, Utrecht, Netherlands</formatted_address>
        <address_component>
            <long_name>De Meern</long_name>
            <short_name>De Meern</short_name>
            <type>political</type>
            <type>sublocality</type>
            <type>sublocality_level_2</type>
        </address_component>
        <address_component>
            <long_name>Vleuten-De Meern</long_name>
            <short_name>Vleuten-De Meern</short_name>
            <type>political</type>
            <type>sublocality</type>
            <type>sublocality_level_1</type>
        </address_component>
        <address_component>
            <long_name>Utrecht</long_name>
            <short_name>Utrecht</short_name>
            <type>locality</type>
            <type>political</type>
        </address_component>
        <address_component>
            <long_name>Utrecht</long_name>
            <short_name>Utrecht</short_name>
            <type>administrative_area_level_2</type>
            <type>political</type>
        </address_component>
        <address_component>
            <long_name>Utrecht</long_name>
            <short_name>UT</short_name>
            <type>administrative_area_level_1</type>
            <type>political</type>
        </address_component>
        <address_component>
            <long_name>Netherlands</long_name>
            <short_name>NL</short_name>
            <type>country</type>
            <type>political</type>
        </address_component>
        <geometry>
            <location>
                <lat>52.0757940</lat>
                <lng>5.0319779</lng>
            </location>
            <location_type>APPROXIMATE</location_type>
            <viewport>
                <southwest>
                    <lat>52.0714898</lat>
                    <lng>5.0196140</lng>
                </southwest>
                <northeast>
                    <lat>52.0904459</lat>
                    <lng>5.0484669</lng>
                </northeast>
            </viewport>
            <bounds>
                <southwest>
                    <lat>52.0714898</lat>
                    <lng>5.0196140</lng>
                </southwest>
                <northeast>
                    <lat>52.0904459</lat>
                    <lng>5.0484669</lng>
                </northeast>
            </bounds>
        </geometry>
        <place_id>ChIJx5fkM1RlxkcR_pIQJLtl5Ro</place_id>
    </result>
</GeocodeResponse>

uj5u.com熱心網友回復：

您的路徑似乎錯誤，是;long_name的孩子 address_component因此，請確保您選擇了該路徑并且不要將相關元素放入謂詞中，例如

Dim name = myXML.SelectSingleNode("GeocodeResponse/result/address_component[type[. = 'sublocality'] and type[. = 'sublocality_level_1']]/long_name")
If name IsNot Nothing Then
  Console.WriteLine("Found: {0}.", name.InnerText)
Else
  Console.WriteLine("Not found.")

標籤：网 VB.net xslt xml文档

上一篇：輸入字串格式不正確|十進制/整數到“NULL”

下一篇：FlatStyle.System不顯示按鈕影像