撰寫一個程式，列印斐波那契數列的第 5 到第 15 個元素。我應該如何從第 5 個開始，即“3”？這是我的代碼
def fibonacci_nums(n):
if n <= 0:
return [0]
sequence = [0, 1]
while len(sequence) <= n:
next_value = sequence[len(sequence) - 1] sequence[len(sequence) - 2]
sequence.append(next_value)
return sequence
print("First 15 Fibonacci numbers:")
print(fibonacci_nums(15))
uj5u.com熱心網友回復：
def fibonacci_nums(n):
if n <= 0:
return [0]
sequence = [0, 1]
while len(sequence) <= n:
next_value = sequence[len(sequence) - 1] sequence[len(sequence) - 2]
sequence.append(next_value)
return sequence[4:]
print("Fibonacci numbers from 5th to 15th number:")
print(fibonacci_nums(14))
uj5u.com熱心網友回復：
這是你需要的：
def fibonacci_nums(n):
if n <= 0:
return [0]
sequence = [0, 1]
while len(sequence) <= n:
next_value = sequence[len(sequence) - 1] sequence[len(sequence) - 2]
sequence.append(next_value)
return sequence
print("First 15 Fibonacci numbers:")
print(fibonacci_nums(15)[4:]) # Print elements from 4th index
輸出：
First 15 Fibonacci numbers:
[3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610]
uj5u.com熱心網友回復：
嘗試這個：
def fibonacci_nums(n, k):
fib=[0,1]
for f in range(k-1):
fib.append(fib[f] fib[f 1])
return fib[n-1:k]
fibonacci_nums(5, 15)
輸出：
[3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377]
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